It should be noted that unlike the other substr functions, the offset value cannot be a negative value.
<?php
echo substr_count('abcdefg', 'efg', 4, 3); // 1
echo substr_count('abcdefg', 'efg', -3, 3); // warning
?>
substr_count
(PHP 4, PHP 5)
substr_count — Count the number of substring occurrences
Description
int substr_count
( string $haystack
, string $needle
[, int $offset
[, int $length
]] )
substr_count() returns the number of times the needle substring occurs in the haystack string. Please note that needle is case sensitive.
Note: This function doesn't count overlapped substrings. See the example below!
Parameters
- haystack
-
The string to search in
- needle
-
The substring to search for
- offset
-
The offset where to start counting
- length
-
The maximum length after the specified offset to search for the substring. It outputs a warning if the offset plus the length is greater than the haystack length.
Return Values
This functions returns an integer.
ChangeLog
| Version | Description |
|---|---|
| 5.1.0 | Added the offset and the length parameters |
Examples
Example #1 A substr_count() example
<?php
$text = 'This is a test';
echo strlen($text); // 14
echo substr_count($text, 'is'); // 2
// the string is reduced to 's is a test', so it prints 1
echo substr_count($text, 'is', 3);
// the text is reduced to 's i', so it prints 0
echo substr_count($text, 'is', 3, 3);
// generates a warning because 5+10 > 14
echo substr_count($text, 'is', 5, 10);
// prints only 1, because it doesn't count overlapped subtrings
$text2 = 'gcdgcdgcd';
echo substr_count($text2, 'gcdgcd');
?>
substr_count
Anonymous
11-Jul-2008 04:49
11-Jul-2008 04:49
danjr33 at gmail dot com
24-Jul-2007 04:37
24-Jul-2007 04:37
I ran into trouble using this function when I moved a script from a server with PHP5 to a server with only PHP4.
As the last two parameters were added with 5.1.0, I wrote a substitute function:
<?php
function substr_count5($str,$search,$offset,$len) {
return substr_count(substr($str,$offset,$len),$search);
}
?>
Use it exactly as substr_count() is used in PHP5. (This will work in PHP5 as well.)
info at fat-fish dot co dot il
06-May-2007 02:07
06-May-2007 02:07
a simple version for an array needle (multiply sub-strings):
<?php
function substr_count_array( $haystack, $needle ) {
$count = 0;
foreach ($needle as $substring) {
$count += substr_count( $haystack, $substring);
}
return $count;
}
?>
flobi at flobi dot com
26-Oct-2006 05:07
26-Oct-2006 05:07
Making this case insensitive is easy for anyone who needs this. Simply convert the haystack and the needle to the same case (upper or lower).
substr_count(strtoupper($haystack), strtoupper($needle))
XinfoX X at X XkarlX X-X XphilippX X dot X XdeX
21-Dec-2003 11:27
21-Dec-2003 11:27
Yet another reference to the "cgcgcgcgcgcgc" example posted by "chris at pecoraro dot net":
Your request can be fulfilled with the Perl compatible regular expressions and their lookahead and lookbehind features.
The example
$number_of_full_pattern = preg_match_all('/(cgc)/', "cgcgcgcgcgcgcg", $chunks);
works like the substr_count function. The variable $number_of_full_pattern has the value 3, because the default behavior of Perl compatible regular expressions is to consume the characters of the string subject that were matched by the (sub)pattern. That is, the pointer will be moved to the end of the matched substring.
But we can use the lookahead feature that disables the moving of the pointer:
$number_of_full_pattern = preg_match_all('/(cg(?=c))/', "cgcgcgcgcgcgcg", $chunks);
In this case the variable $number_of_full_pattern has the value 6.
Firstly a string "cg" will be matched and the pointer will be moved to the end of this string. Then the regular expression looks ahead whether a 'c' can be matched. Despite of the occurence of the character 'c' the pointer is not moved.
